Discussion :: Time and Work
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A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Answer : Option C
Explanation :
Let A's 1 day's work = x and B's 1 day's work = y.
| Then, x + y = | 1 | and 16x + 44y = 1. |
| 30 |
| Solving these two equations, we get: x = | 1 | and y = | 1 |
| 60 | 60 |
B's 1 day's work = | 1 | . |
| 60 |
Hence, B alone shall finish the whole work in 60 days.
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B's 1 day's work =