Discussion :: Time and Work
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A and B can do a job together in 7 days. A is 1\(\frac {3 } { 4 } \)times as efficient as B. The same job can be done by A alone in :
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A.
9\( \frac { 1 } {3 } \)days |
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B.
11 days |
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C.
12\(\frac { 1 } { 4 } \)days |
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D.
16\( \frac { 1 } {3 } \)days |
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Answer : Option B
Explanation :
(A's 1 day's work) : (B's 1 day's work) =\(\frac { 7 } {4 } \):1=7:4
Let A's and B's 1 day's work be 7x and 4x respectively.
Then, 7x + 4x =\( \frac { 1 } {7 } \) 
11x =\( \frac { 1 } {7 } \) x =\( \frac { 1 } {7 7} \)
A's 1 day's work =[\( \frac { 1 } {7 7} *7]\)=\( \frac { 1 } {11} \)
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