Discussion :: Time and Work

A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:
Answer : Option C
Explanation :
(B + C)'s 1 day's work =\([ \frac { 1 } { 9 }+\)\( \frac { 1 } {1 2 }]\)=\(\frac { 7 } { 36 } \)
Work done by B and C in 3 days =[\(\frac { 7 } { 36 } *3]\)=\( \frac { 7 } {1 2 }\)
Remaining work =[1\( \frac { 7 } {1 2 }\)]=\( \frac { 5 } {1 2 }\)
Now,\(\frac { 1 } { 24 } \)work is done by A in 1 day
So,\( \frac { 5 } {1 2 }\)work is done by A in[\( 24*\frac { 5 } {1 2 } ]\)=10days
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