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### Discussion :: Time and Work

1.  A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :
2.  A. 8 days B. 10 days C. 12 days D. 15 days

Explanation :

(A + B)'s 1 day's work =[$$\frac { 1 } { 15}$$+$$\frac { 1 } { 10}$$]=$$\frac { 1 } {6 }$$

Work done by A and B in 2 days =[$$\frac { 1 } {6 } *2]$$=$$\frac { 1 } {3 }$$

Remaining work =[1-$$\frac { 1 } {3 }$$]=$$\frac { 2 } {3 }$$

Now,  $$\frac { 1 } {15 }$$work is done by A in 1 day.

$$\frac { 2 } {3 }$$work will be done by a in[15$$*\frac { 2 } { 3 }$$]= 10 days.

Hence, the total time taken = (10 + 2) = 12 days.

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