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### Discussion :: Time and Work

1. A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:

2.  A. 15 days B. 20 days C. 25 days D. 30 days

Explanation :

(A + B)'s 1 day's work =$$\frac { 1 } {10 }$$

C's 1 day's work =$$\frac { 1 } {50 }$$

(A + B + C)'s 1 day's work =[$$\frac { 1 } {10 }$$+$$\frac { 1 } {50 }$$]=$$\frac { 6 } {50 }$$=$$\frac { 3 } {25}$$.... (i)

A's 1 day's work = (B + C)'s 1 day's work .... (ii)

From (i) and (ii), we get: 2 x (A's 1 day's work) =$$\frac { 3 } {25}$$

A's 1 day's work =$$\frac { 3 } {50}$$

B's 1 day's work[$$\frac { 1 } {10 }$$-$$\frac { 3 } {50 }$$]=$$\frac { 2 } {50}$$=$$\frac { 1 } {25 }$$

So, B alone could do the work in 25 days.

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