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### Discussion :: Time and Work

1.  If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
2.  A. 4 days B. 5 days C. 6 days D. 7 days

Answer : Option A

Explanation :

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y =$$\frac { 1 } { 10 }$$and 26x + 48y =$$\frac { 1 } { 2 }$$

Solving these two equations, we get : x =$$\frac { 1 } { 100 }$$and y =$$\frac { 1 } { 200 }$$

(15 men + 20 boy)'s 1 day's work =[$$\frac { 15 } { 100 }$$+$$\frac { 20 } { 200 }$$]=$$\frac { 1 } { 4}$$

15 men and 20 boys can do the work in 4 days.

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