Surds and Indices - Arithmetic Aptitude Questions and Answers

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\(\frac { 1 } { 1+a^(n-m) } +\)\(\frac { 1 } { 1+a^(m-n) }=?\)

\(\frac { 1 } { 2 } \)

a^m + n

Answer : Option C

Explanation :

\(\frac { 1 } { 1+a^(n-m) } +\)\(\frac { 1 } { 1+a^(m-n) }=\)\( \frac { 1 } {[1+ a^n/a^m]}+\)\( \frac { 1 } {[1+ a^m/a^n]}\)

=\( \frac {a^m } { (a^m+a^n)} \)+\( \frac {a^n } { (a^m+a^n)} \)

=\( \frac { (a^m+a^n) } { (a^m+a^n)} \)

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