Square Root and Cube Root - Arithmetic Aptitude Questions and Answers

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If a = 0.1039, then the value of \(\sqrt{4a^2-4a+1+3a}\) is :

0.1039

0.2078

1.1039

2.1039

Answer : Option C

Explanation :

\(\sqrt{4a^2-4a+1+3a}\) = \(\sqrt{(1)^2+(2a)^2-2*1*2a+3a}\)

= \(\sqrt{(1-2a)^2} \) + 3a

= (1 - 2a) + 3a

= (1 + a)

= (1 + 0.1039)

= 1.1039

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