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### Discussion :: Simplification

1.  A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
2.  A. 30 birds B. 60 birds C. 72 birds D. 90birds

Explanation :

Let the total number of shots be x. Then,

shots fired by A=  $$\frac { 5 } { 8 } X$$

shots fired byB=$$\frac { 3 } { 8 } X$$

Killing shots by A =$$\frac { 1 } { 3 }$$of$$\frac { 5 } { 8 } X$$=$$\frac { 5} { 24 }X$$

Shots missed by B =$$\frac { 1 } { 2 }$$of$$\frac { 3 } { 8 } X$$=$$\frac { 3 } { 16 }X$$

$$\frac { 3X } { 16 }$$=27or X=$$[\frac { 27*16 } {3}]$$=144

Birds killed by A =$$\frac { 5X} { 24 }$$=$$[ \frac { 5 } { 24 }*144]$$=30

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