Discussion :: Races and Games
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A runs 1\(\frac { 2 } { 3 } \) times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
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Answer : Option A
Explanation :
Ratio of the speeds of A and B =\(\frac { 5 } { 3 } \):1= 5:3
Thus, in race of 5 m, A gains 2 m over B.
2 m are gained by A in a race of 5 m
80 m will be gained by A in race of [\(\frac { 5 } { 2 } \) x 80 ]m = 200m
Winning post is 200 m away from the starting point.
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