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Discussion :: Quadratic Equations

  1. I. 9a2 + 18a + 5 = 0,
    II. 2b2 + 13b + 20 = 0 to solve both the equations to find the values of a and b?
    2. A.
    If a > b
    B.
    If a ≥ b
    C.
    If a < b
    D.
    If a ≤ b
    E.
    If a = b or the relationship between a and b cannot be established.

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    Answer : Option A

    Explanation :

    I. 9a2 + 3a + 15a + 5 = 0
    =>(3a + 5)(3a + 1) = 0 => a = -5/3, -1/3
    II. 2b2 + 8b + 5b + 20 = 0
    =>(2b + 5)(b + 4) = 0 => b = -5/2, -4
    a is always more than b.
    a > b.

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