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Discussion :: Quadratic Equations

  1. I. x2 + 11x + 30 = 0,
    II. y2 + 15y + 56 = 0 to solve both the equations to find the values of x and y?
    2. A.
    If x < y
    B.
    If x > y
    C.
    If x ≤ y
    D.
    If x ≥ y
    E.
    If x = y or the relationship between x and y cannot be established.

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    Answer : Option B

    Explanation :

    I. x2 + 6x + 5x + 30 = 0
    =>(x + 6)(x + 5) = 0 => x = -6, -5
    II. y2 + 8y + 7y + 56 = 0
    =>(y + 8)(y + 7) = 0 => y = -8, -7
    => x > y

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