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Discussion :: Quadratic Equations

  1. I. x2 + 3x - 18 = 0,
    II. y2 + y - 30 = 0 to solve both the equations to find the values of x and y?
    2. A.
    If x < y
    B.
    If x > y
    C.
    If x ≤ y
    D.
    If x ≥ y
    E.
    If x = y or the relationship between x and y cannot be established.

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    Answer : Option E

    Explanation :

    I. x2 + 6x - 3x - 18 = 0
    =>(x + 6)(x - 3) = 0 => x = -6, 3
    II. y2 + 6y - 5y - 30 = 0
    =>(y + 6)(y - 5) = 0 => y = -6, 5
    No relationship can be established between x and y.

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