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Discussion :: Quadratic Equations

  1. I. x2 - x - 42 = 0,
    II. y2 - 17y + 72 = 0 to solve both the equations to find the values of x and y?
    2. A.
    If x < y
    B.
    If x > y
    C.
    If x ≤ y
    D.
    If x ≥ y
    E.
    If x = y or the relationship between x and y cannot be established.

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    Answer : Option A

    Explanation :

    I. x2 - 7x + 6x - 42 = 0
    => (x - 7)(x + 6) = 0 => x = 7, -6
    II. y2 - 8y - 9y + 72 = 0
    => (y - 8)(y - 9) = 0 => y = 8, 9
    => x < y

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