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Discussion :: Quadratic Equations

  1. I. a2 + 8a + 16 = 0,
    II. b2 - 4b + 3 = 0 to solve both the equations to find the values of a and b?
    2. A.
    If a < b
    B.
    If a ≤ b
    C.
    If the relationship between a and b cannot be established
    D.
    If a > b
    E.
    If a ≥ b

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    Answer : Option A

    Explanation :

    I. (a + 4)2 = 0 => a = -4
    II.(b - 3)(b - 1) = 0
    => b = 1, 3 => a < b

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