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  1.  What is the speed of the train whose length is 210 metres?

    I. The train crosses another train (Howrah Express/12869) of 300 metres length running in opposite direction in 10 seconds.

     II. The train crosses another train (Howrah Express/12869) running in the same direction at the speed of 60 km/hr in 30 seconds.

     

  2. A.

    I alone sufficient while II alone not sufficient to answer

    B.

    II alone sufficient while I alone not sufficient to answer

    C.

    Either I or II alone sufficient to answer

    D.
    Both I and II are not sufficient to answer
    E.

    Both I and II are necessary to answer

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    Answer : Option E

    Explanation :

     

    Time taken to cross the train,
    running in opposite directions
    =   \(\frac { (l1+l2) } { (u+v) } sec\)
     

     

     10 = \(\frac { (210+300) } { (u+v) } \)  
     

        u + v = 51.

     

    Time taken to cross the train, running in same direction =   \( \frac { (l1+l2) } { (u-v) } sec\)sec.
     

     

     30 = \(\frac { (210+300) } { ((u-60) \times(5/8))} sec\)  
     

     

     

     u = \( (17+\frac{50}{3})m/sec\)
       Thus, u and v can be obtained.
         


     Correct answer is (E).

     

     

     


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