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  1. A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?

  2. A.

    69.5 km/hr

    B.

    70 km/hr

    C.

    79 km/hr

    D.

    79.2 km/hr

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    Answer : Option D

    Explanation :

    Let the length of the train be x metres and its speed by y m/sec.

     

    Then,   \(\frac { x} { y } \) =8       x = 8y
     

     

    now,\(\frac{x+264}{20}=y\)


     8y + 264 = 20y

     

    speed= 22 m/sec=\((22\times\frac { 18 } { 5 } ) km/hr = 79.2 km/hr\)

     

     


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