Discussion :: Problems on Trains
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Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
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Answer : Option C
Explanation :
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
 \([\frac { 100+100 } {8 } ]\) |
= 3x | |
24x = 200
| x = \(\frac { 25 } { 3 } \) |
. | |
| So, speed of the faster train = \(\frac {50 } { 3} \) | m/sec | |
| = [\(\frac {50 } { 3} \) | x \( \frac { 18 } { 5} ]\) | km/hr | |||||||
= 60 km/hr.
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