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  1. Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
    2. A.

    36
    B.

    45
    C.

    48
    D.

    49

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    Answer : Option A

    Explanation :

    Relative speed = (60+ 90) km/hr

     

           

      =  \([150* \frac { 5 } { 18 } ]\)     m/sec

     

     

       =  \([\frac { 125 } {3 } ]\)   m/sec.
     

     

    Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

     

    Required time =[ 2000 x \(\frac { 3 } { 125 } ]\)       sec = 48 sec.
     

     

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