Discussion :: Problems on Trains
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Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer : Option A
Explanation :
Relative speed = (60+ 90) km/hr
= | [150∗518] | m/sec | ||
|
= | [1253] | m/sec. | |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time =[ 2000 x 3125] | sec = 48 sec. | |||
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