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### Discussion :: Problems on H.C.F and L.C.M

1.  If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:
2.  A. $$\frac { 55 } { 601}$$ B. $$\frac { 601 } { 55 }$$ C. $$\frac { 11 } { 120 }$$ D. $$\frac { 120 } {11 }$$

The required sum =$$\frac { 1 } {a }$$+$$\frac { 1 } { b }$$=$$\frac { a+b } {ab }$$=$$\frac { 55 } { 600 }$$=$$\frac { 11 } { 120 }$$