Problems on H.C.F and L.C.M - Arithmetic Aptitude Questions and Answers

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Discussion :: Problems on H.C.F and L.C.M

If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

$\frac { 55 } { 601}$

$\frac { 601 } { 55 }$

$\frac { 11 } { 120 }$

$\frac { 120 } {11 }$

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Answer : Option C

Explanation :

Let the numbers be a and b.

Then, a + b = 55 and ab = 5 x 120 = 600.

The required sum = $\frac { 1 } {a }$ + $\frac { 1 } { b }$ = $\frac { a+b } {ab }$ = $\frac { 55 } { 600 }$ = $\frac { 11 } { 120 }$

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