Problems on H.C.F and L.C.M - Arithmetic Aptitude Questions and Answers

Home / Arithmetic Aptitude / Problems on H.C.F and L.C.M :: Discussion

The H.C.F. of $\frac { 9 } { 10 }$ , $\frac { 12 } { 25 }$ , $\frac { 1 8} { 35}$ and $\frac { 21 } { 40 }$ is:

$\frac { 3 } {5 }$

$\frac {252 } {5 }$

$\frac {3 } { 1400 }$

$\frac { 63 } {700 }$

Answer : Option C

Explanation :

Required H.C.F. = $\frac {H.C.F.of 9,12,18,21} { L.C.M.of 10,25,35,40 } =$ $\frac { 3 } { 1400 }$

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