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Discussion :: Problems on H.C.F and L.C.M

  1. The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

  2. A.

    28

    B.

    32

    C.

    40

    D.

    64

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    Answer : Option A

    Explanation :

    Let the numbers be 2x and 3x.

    Then, their L.C.M. = 6x.

    So, 6x = 48 or x = 8.

     The numbers are 16 and 24.

    Hence, required sum = (16 + 24) = 40.


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