Problems on H.C.F and L.C.M - Arithmetic Aptitude Questions and Answers

Home / Arithmetic Aptitude / Problems on H.C.F and L.C.M :: Discussion

Find the smallest digit that will leave same remainder 4 in each case when divided by 12, 15, 20, and 54.

454

540

544

450

Answer : Option C

Explanation :

Take LCM of 12, 15, 20, and 54. It will be = 540.

ATQ, the remainder in each case = 4.

Hence, the required number = 540+4 = 544.

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