Problems on H.C.F and L.C.M - Arithmetic Aptitude Questions and Answers

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Find the least number which when divided by 5, 6, 7, and 8 leaves remainder 3, but when divided by 9 leaves remainder 0.

843

1683

2523

3363

Answer : Option B

Explanation :

Take LCM of 5, 6, 7, and 8. It will be = 840.

Let the number 840*x + 3 is completely divisible by 9 if the sum of digits is divisible by 9.

Let x= 2, the number will be 1683, and the sum of its digits is equals to 18 which is divisible by 9. So, the required number is 1683.

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