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Discussion :: Problems on H.C.F and L.C.M

  1. The least number which when divided by 2, 3, 4, 5 and 6 leaves the same remainder 1 in each case. If the same number is divided by 7, it leaves no remainder. Find the number.

    2. A.
    231
    B.
    301
    C.
    371
    D.
    441

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    Answer : Option B

    Explanation :

    LCM of 2, 3, 4, 5, 6

    Aptitude H.C.F and L.C.M

    LCM = 2 x 2 x 3 x 5 = 60

    Now, 60 x 1 + 1 = 61 is not divisible by 7

    60 x 2 + 1 = 121 is not divisible by 7

    60 x 5 + 1 = 301 is divisible by 7

    Hence 301 is the number.

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