Arithmetic Aptitude :: Problems on Ages
1. If the current age is x, then n times the age is nx.
2. If the current age is x, then age n years later/hence = x + n.
3. If the current age is x, then age n years ago = x - n.
4. The ages in a ratio a : b will be ax and bx.
5. If the current age is x , then \(\frac { 1 } { n } \) of the age is \(\frac {X} { n } \)