Problems on Ages - Arithmetic Aptitude Questions and Answers

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Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son?

34, 9

33, 7

35, 5

36, 6

Answer : Option A

Explanation :

Let age of son 4 years ago be = X

So, age of man 4 years ago would be = 6X

As per question after 16 years;

2* age of son = age of man

2(X + 4 +16) = (6X + 4 + 16)

2X +40 = 6X + 20

2X - 6X = 20 - 40

- 4X = - 20

X = 5 years

∴Present age of son = 5 + 4= 9 years

Present age of man = 6X + 4= 6*5 + 4 = 30 +4 = 34 years

Solution 2:

Apply formula; A's (man) present age+ t1