Discussion :: Problems on Ages

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer : Option A
Explanation :
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
(4x + 8) =\( \frac {5 } { 2 } \)(x + 8)
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio =\(\frac { (4X+16 )} { (X+16 )}=\)\( \frac { 48 } { 24 }\)=2
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