Probability - Arithmetic Aptitude Questions and Answers

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Three unbiased coins are tossed. What is the probability of getting at most two heads?

\( \frac { 3 } {4}\)

\( \frac { 1 } {4}\)

\( \frac { 3 } {8}\)

\( \frac { 7 } {8}\)

Answer : Option D

Explanation :

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) = \(\frac { n(E) } { n(S)} \) =\( \frac { 7 } {8}\)

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