Discussion :: Probability
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Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
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A.
\(\frac { 1 } { 2 }\) |
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B.
\(\frac { 2 } { 5 }\) |
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C.
\( \frac { 8 } {15 }\) |
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D.
\(\frac { 9 } { 20 } \) |
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Answer : Option D
Explanation :
Here, S = {1, 2, 3, 4, ...., 19, 20}.
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
P(E) = \(\frac { n(E) } { n(S) } \) =\(\frac { 9 } { 20 } \)
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