Discussion :: Probability
- A bag contains 2 red, 3 green and 2 blue balls.Two balls are drawn at random.What is the probability that none of the drawn ball is blue?
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Answer : Option B
Explanation :
Possible out comes(E) or Favourable outcomes are
E1.2 red ball or
E2.2 green ball or
E3.1 red and 1 green
Number of selecting 2 balls from two red balls n(E)=2C2=1
Number of ways of selecting 2 balls from 3 green balls n(E2)= 3C2=3
Number of ways of selecting 1 red ball and 1 green ball n(E3)= 2C1*3C1=2*3=6
Sample space S=Number of ways of selecting 2 balls from 7(2+3+2) balls n(S)=7C2=21
n(E)=n(E1)+ n(E2)+ n(E3)=1+3+6=10
Required probability P(E)=n(E)/n(S)=10/21
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