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Discussion :: Probability

  1.  In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?

    2. A.

    2/3
    B.

    3/7
    C.

    8/21
    D.

    9/22

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    Answer : Option C

    Explanation :

    Total number of balls = (8 + 7 + 6) = 21
    Let E = event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.
    Therefore, n(E) = 8.
    P(E) = 8/21.

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