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  1.  Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?

    2. A.

    1/2
    B.

    1/4
    C.

    1/6
    D.

    1/8

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    Answer : Option A

    Explanation :

    Total cases are = 2*2*2 = 8, which are as follows
    [TTT, HHH, TTH, THT, HTT, THH, HTH, HHT]

    Favoured cases are = [TTH, THT, HTT, TTT] = 4

    So required probability = 4/8 = 1/2

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