Pipes and Cistern - Arithmetic Aptitude Questions and Answers

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Discussion :: Pipes and Cistern

Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:

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Answer : Option C

Explanation :

Part filled in 2 hours = $\frac { 2 } { 6 }$ = $\frac {1 } { 3 }$

Remaining part =[1- $\frac {1 } { 3 }$ ]= $\frac {2 } { 3 }$

(A + B)'s 7 hour's work = $\frac {2 } { 3 }$

(A + B)'s 1 hour's work = $\frac {2 } { 21 }$

C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }

=[ $\frac { 1 } {6}$ - $\frac {2 } { 21 }$ ] = $\frac { 1 } {14}$

C alone can fill the tank in 14 hours.

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