Pipes and Cistern - Arithmetic Aptitude Questions and Answers

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Discussion :: Pipes and Cistern

A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?

3 hrs 15 min

3 hrs 45 min

4 hrs

4 hrs 15 min

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Answer : Option B

Explanation :

Time taken by one tap to fill half of the tank = 3 hrs.

Part filled by the four taps in 1 hour =[ 4 X $\frac { 1 } { 6}$ ] = $\frac { 2} { 3}$

Remaining part =[1- $\frac { 1 } { 2}$ ] = $\frac { 1 } { 2}$

$\frac { 2} { 3}$ : $\frac { 1 } { 2}$ :;1:x

x = [ $\frac { 1 } { 2}$ X 1 X $\frac { 3 } { 2}$ ] = $\frac { 3} { 4}$ hours i.e., 45 mins