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Discussion :: Pipes and Cistern

  1. A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?

    2. A.

    15 min
    B.

    20 min
    C.

    27.5 min
    D.

    30 min

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    Answer : Option D

    Explanation :

    Part filled by (A + B) in 1 minute = [\(\frac { 1 } { 60 } \)+\(\frac { 1 } { 40 } ]\) =\(\frac { 1 } {24 } \)

     

    Suppose the tank is filled in x minutes.

     

    Then,\(\frac { X} { 2 }\)[\(\frac { 1 } {24 } \)+\(\frac { 1 } { 40 } ]\)=1 

     

      \(\frac { X} { 2 }\) X  \(\frac { 1 } {15 } \) =1

     

     x = 30 min.

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