Discussion :: Pipes and Cistern
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A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
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Answer : Option C
Explanation :
Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take\(\frac { X } { 2 } \) and\(\frac { X } {4 } \)hours respectively to fill the tank
\(\frac { 1 } { X } \)+\(\frac { 2 } { X } \)+\(\frac { 4 } { X } \)=\(\frac { 1 } {5 } \)
\(\frac { 7 } { X } \)=\(\frac { 1 } {5 } \)
x = 35 hrs.
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