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### Discussion :: Permutation and Combination

1.  In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
2.  A. 63 B. 90 C. 126 D. 45 E. 135

Required   number of ways  =   (7C5 x 3C2) = (7C2 x 3C1) =[$$\frac { 7*6 } { 2*1 }$$x3]=63