In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
63
90
126
45
135
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Answer : Option A
Explanation :
Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) =[\( \frac { 7*6 } { 2*1 }\)x3]=63
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