Discussion :: Percentage
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The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
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Answer : Option B
Explanation :
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
\({87500 \over 175000}\)x 100 |  % = 50%. |
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Required average = \([\frac { 50 } { 10} ]\) % = 5 %
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