Discussion :: Percentage

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer : Option C
Explanation :
Let their marks be (x + 9) and x.
Then, x +9 = \( \frac { 56} { 100 } \)(x+9+x)
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
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