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Discussion :: Numbers

1. A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be

2.  A. 1, 2 B. 2, 3 C. 3, 2 D. 4, 1

Explanation :

4 | x            y = (5 x 1 + 4) = 9
--------
5 | y -1         x = (4 x y + 1) = (4 x 9 + 1) = 37
--------
| 1 -4

Now, 37 when divided successively by 5 and 4, we get

5 | 37
---------
4 | 7 - 2
---------
| 1 - 3

Respective remainders are 2 and 3.

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