Home / Arithmetic Aptitude / Numbers :: Discussion

### Discussion :: Numbers

1. A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:

2.  A. 214 B. 476 C. 954 D. 1908

Answer : Option A

Explanation :

4 | x            z = 6 x 1 + 4  = 10
-----------
5 | y -2         y = 5 x z + 3  = 5 x 10 + 3  = 53
-----------
6 | z - 3        x = 4 x y + 2  = 4 x 53 + 2  = 214
-----------
| 1 - 4

Hence, required number = 214.

Be The First To Comment