Discussion :: Numbers
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The sum of how many terms of the series 6 + 12 + 18 + 24 + ... is 1800 ?
Answer : Option B
Explanation :
This is an A.P. in which a = 6, d = 6 and Sn = 1800
Then, \(\frac { n } { 2 } \) [2a + (n - 1)d] = 180
3n (n + 1) = 1800
n(n + 1) = 600
n2 + n - 600 = 0
n2 + 25n - 24n - 600 = 0
n(n + 25) - 24(n + 25) = 0
(n + 25)(n - 24) = 0
n = 24
Number of terms = 24.
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