Numbers - Arithmetic Aptitude Questions and Answers

Home / Arithmetic Aptitude / Numbers :: Discussion

(1² + 2² + 3² + ... + 10²) = ?

330

345

365

385

Answer : Option D

Explanation :

We know that (1² + 2² + 3² + ... + n²) =\( \frac { 1 } { 6 } \)n(n + 1)(2n + 1)

Putting n = 10, required sum =\( [\frac { 1 } { 6 } *10*11*21]\)

= 385

Be The First To Comment

Comments

Name