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  1. The sum of the two numbers is 12 and their product is 35. What is the sum of the reciprocals of these numbers ?

  2. A.

    \(\frac {12} {35 } \)

    B.

    \(\frac {1} {35 } \)

    C.

    \(\frac {35} {8 }\)

    D.

    \(\frac {7 } {3 2 } \)

     

     

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    Answer : Option A

    Explanation :

    Let the numbers be a and b. Then, a + b = 12 and ab = 35

     \( \frac { a+b } { ab } \)=\(\frac {12} {35 } \)   \( [ \frac { 1 } { b }+\)\(\frac { 1 } { a}] \)=\(\frac {12} {35 } \)

     Sum of reciprocals of given numbers =\(\frac {12} {35 } \)


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