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  1. How many 3 digit numbers are divisible by 6 in all ?

  2. A.

    149

    B.

    150

    C.

    151

    D.

    166

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    Answer : Option B

    Explanation :

    Required numbers are 102, 108, 114, ... , 996

    This is an A.P. in which a = 102, d = 6 and l = 996

    Let the number of terms be n. Then,

    a + (n - 1)d = 996

       102 + (n - 1) x 6 = 996

       6 x (n - 1) = 894

       (n - 1) = 149

       n = 150.


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