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  1. The difference between a positive proper fraction and its reciprocal is 9/20. The fraction is:

    2. A.

    \( {3\over 5}\)

     

     

     
    B.

    \( {3\over 10}\)
    C.

    \( {4\over5}\)
    D.

    \( {4\over3}\)

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    Answer : Option C

    Explanation :


    Let the required fraction be x. Then\( 23 (\frac { 1 } { 2 } ) 4^3 \)-X=\( {9\over 20}\)

       \(\)\( {1-X^2\over X}\)=\( {9\over 20}\)

         20 - 20x2 = 9x  \(\)

         20x2 + 9x - 20 = 0

         20x2 + 25x - 16x - 20 = 0

         5x(4x + 5) - 4(4x + 5) = 0

         (4x + 5)(5x - 4) = 0

         x =\( {4\over 5}\)

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