Discussion :: Numbers

It is being given that (2^{32} + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Answer : Option D
Explanation :
Let 2^{32} = x. Then, (2^{32} + 1) = (x + 1).
Let (x + 1) be completely divisible by the natural number N. Then,
(2^{96} + 1) = [(2^{32})^{3} + 1] = (x^{3} + 1) = (x + 1)(x^{2}  x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
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