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### Discussion :: Height and Distance

1. From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

2.  A. 149 m B. 156 m C. 173 m D. 200 m

Explanation :

Let AB be the tower.

Then, APB = 30° and AB = 100 m.

 $$\frac { AB } { AP }$$= tan 30° =$$\frac { 1 } { 3 }$$

 AP = (AB x 3) m = 1003 m = (100 x 1.73) m = 173 m

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