Height and Distance - Arithmetic Aptitude Questions and Answers

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An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of the tower is:

21.6 m

23.2 m

24.72 m

None of these

Answer : Option A

Explanation :

Let AB be the observer and CD be the tower.

Draw BE CD.

Then, CE = AB = 1.6 m,

BE = AC = 203 m.

	\(\frac { DE } { BE } \)= tan 30° = \(\frac {1} { 3 } \)
	\(\frac { DE } { BE } \)= tan 30° = \(\frac {1} { 3 } \)

DE =		\(\frac { 203 } { 3 } \)m = 20 m.